A.Adding the KB and the BM
B.Subtracting the KB from the BM
C.Subtracting the GM from the KB
D.Adding the GM and the KB
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A.metacenter
B.center of buoyancy
C.center of flotation
D.center of gravity
A.the load line becomes submerged
B.a non-watertight opening is at still water level
C.offset becomes excessive
D.reserve buoyancy is a maximum
A.metacentric height
B.height of the righting arm
C.fore and aft perpendicular
D.height of the center of buoyancy
A.list
B.heel
C.trim
D.flotation
A.about which the vessel lists and trims
B.which coincides with the center of buoyancy
C.which,in the absence of external forces,is always vertically aligned with the center of gravity
D.which is shown in the hydrostatic tables as VCB
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At all angles of inclination,the metacenter is().
The difference between the height of the metacenter and the height of the center of gravity is known as the().
Semisubmersibles A and B are identical. However,A is more tender than B. This means that A relative to B has a().
All of the following can be determined by use of a stabilogauge EXCEPT().
The KM for a vessel may be determined by which of the following?().
That center around which a vessel trims is called the().
For a vessel inclined by the wind,multiplying the buoyant force by the horizontal distance between the lines of action of the buoyant and gravity forces gives the().
Horizontal fore or aft motion of a vessel is known as().
Angular motion about the longitudinal axis of a vessel is known as().
The existence of liquids in partially full tanks or compartments of a ship causes a virtual rise in the height of the().