A.metacentric height
B.mean draft
C.moment to trim one inch
D.deadweight
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A.lower than the center of gravity
B.at the same height as the center of gravity
C.higher than the baseline
D.on the longitudinal centerline
A.free surface effects are reduced due to pocketing
B.KG is reduced as the vessel seeks the angle of loll
C.effective beam is increased causing BM to increase
D.underwater volume of the hull is increased
A.vertically above the center of buoyancy
B.vertically above the center of gravity
C.at the intersection of the upright vertical centerline and the line of action of the buoyant force
D.at the geometric center of the underwater volume
A.The foot/tons needed to trim the vessel by 1 inch
B.The foot/tons needed to trim the vessel by 1 foot
C.The moments needed to trim the vessel by 1 centimeter
D.The amount of vessel will trim when loading 100 tons 100 feet from the tipping Center
A.The metacenter does not remain in the same position for large angles of inclination
B.The center of gravity shifts due to inclination
C.The center of gravity shifts above the metacenter as the vessel is inclined
D.The mean draft will change as the vessel is inclined
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A ship lists and trims about the().
For small angles of inclination,if the KG were equal to the KM,then the vessel would have().
Forces within a vessel have caused a difference between the starboard and port drafts. This difference is called().
Deballasting a double bottom has what affect on KG?().
A load line of a ship is assigned by().
For a given displacement,the righting arm has its maximum value when().
()we have worked out the loading plan,we shall start doing more revision work.
An upright vessel has negative GM. GM becomes positive at the angle of loll because the().
A ship is inclined at an angle of loll. In the absence of external forces,the righting arm (GZ) is().
A vessel with a large GM will().