A.lower than the center of gravity
B.at the same height as the center of gravity
C.higher than the baseline
D.on the longitudinal centerline
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A.free surface effects are reduced due to pocketing
B.KG is reduced as the vessel seeks the angle of loll
C.effective beam is increased causing BM to increase
D.underwater volume of the hull is increased
A.vertically above the center of buoyancy
B.vertically above the center of gravity
C.at the intersection of the upright vertical centerline and the line of action of the buoyant force
D.at the geometric center of the underwater volume
A.The foot/tons needed to trim the vessel by 1 inch
B.The foot/tons needed to trim the vessel by 1 foot
C.The moments needed to trim the vessel by 1 centimeter
D.The amount of vessel will trim when loading 100 tons 100 feet from the tipping Center
A.The metacenter does not remain in the same position for large angles of inclination
B.The center of gravity shifts due to inclination
C.The center of gravity shifts above the metacenter as the vessel is inclined
D.The mean draft will change as the vessel is inclined
A.list
B.heel
C.trim
D.flotation
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A floating vessel will behave as if all of its weight is acting downward through the().
An upright vessel has negative GM. GM becomes positive at the angle of loll because the().
An unstable upright equilibrium position on a vessel means that the metacenter is().
Forces within a vessel have caused a difference between the starboard and port drafts. This difference is called().
For a ship with longitudinal inclination,an increase in GML causes().
What is MTI?().
The geometric center of the waterplane area is called the().
A slow and easy motion of a vessel in a seaway is an indication of a().
All of the following can be determined by use of a stabilogauge EXCEPT().
A ship lists and trims about the().